How to calculate a 100% Profit boost ticket

  • Hi,

    I have been given an 100% Profit boost ticket, but I have to make a selection with minimum 3 bets.

    So if I find 3 bets, how do I need to calculate how much to lay it for?

    I know that the 3 games must be played at overlapping times in order to lay the other bets if the first one is a winner.

    Thanks in advance!

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    Matt
    Keymaster
    1502

    You can use my Sequential Lay Calculator for this > https://matchedbettingblog.com/sequential-lay-calculator/.

    You just need to enter your boosted odds as the back odds and ensure that your three selected matches don’t overlap.

    +0
    Silverspeed 1

    Hi Matt,

    The problem there is when that the first match is a loss then the calculator is setup up to win 0.

    Example:

    Leg 1 loses
    £ 25.00
    £ 25.00
    = £ 0.00
    Leg 2 loses
    £ 25.00
    £ 27.92 £ 52.92
    = £ 0.00
    Leg 3 loses
    £ 25.00
    £ 27.92 £ 59.10 £ 177.16
    = £ 65.14
    All legs win
    £ 350.00
    £ 27.92 £ 59.10 £ 197.84
    = £ 65.14

    So I want to use it as where my profit would be the same outcome on all legs instead of Risk free or Guaranteed Profit?
    I hope you understand me what I’m trying to say here.

    Thanks.

    +0
    Matt
    Keymaster
    1502

    Unfortunately, the calculator isn’t able to break it down in that way.

    When it comes to the last leg, we have a choice between locking in a guaranteed profit or letting it run for a risk-free shot at a larger potential return.

    +0
    Silverspeed 1

    What should I do then with the odds?

    Pick the first two bets and hope they win?

    Do you have any tips for that one? Ofcourse I know that the first game could be a loss and then?

    Thanks!

    +0
    Ryan Berry 10

    Probably too late for you now but..

    You could lay an accumulator on Smarkets and find the exact same 3 fold on your bookmaker

    With the 100% boost there will be a decent amount of profit in the odds

    +2
    Silverspeed 1

    Hey Ryan,

    Yeah that could be a solution to thanks!

    +0
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